228x-12x^2=0

Solution for 228x-12x^2=0 equation:

228x-12x^2=0

a = -12; b = 228; c = 0;
Δ = b2-4ac
Δ = 2282-4·(-12)·0
Δ = 51984
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{51984}=228$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(228)-228}{2*-12}=\frac{-456}{-24}
=+19
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(228)+228}{2*-12}=\frac{0}{-24}
=0
$